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6y^2=5y+50
We move all terms to the left:
6y^2-(5y+50)=0
We get rid of parentheses
6y^2-5y-50=0
a = 6; b = -5; c = -50;
Δ = b2-4ac
Δ = -52-4·6·(-50)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-35}{2*6}=\frac{-30}{12} =-2+1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+35}{2*6}=\frac{40}{12} =3+1/3 $
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